Provided Methods

fn advance_back_by(self: &mut Self, n: usize) -> Result<(), NonZero<usize>>

Advances the iterator from the back by n elements.

advance_back_by is the reverse version of advance_by. This method will eagerly skip n elements starting from the back by calling next_back up to n times until None is encountered.

advance_back_by(n) will return Ok(()) if the iterator successfully advances by n elements, or a Err(NonZero<usize>) with value k if None is encountered, where k is remaining number of steps that could not be advanced because the iterator ran out. If self is empty and n is non-zero, then this returns Err(n). Otherwise, k is always less than n.

Calling advance_back_by(0) can do meaningful work, for example Flatten can advance its outer iterator until it finds an inner iterator that is not empty, which then often allows it to return a more accurate size_hint() than in its initial state.

Examples

Basic usage:

#![feature(iter_advance_by)]

use std::num::NonZero;

let a = [3, 4, 5, 6];
let mut iter = a.iter();

assert_eq!(iter.advance_back_by(2), Ok(()));
assert_eq!(iter.next_back(), Some(&4));
assert_eq!(iter.advance_back_by(0), Ok(()));
assert_eq!(iter.advance_back_by(100), Err(NonZero::new(99).unwrap())); // only `&3` was skipped

fn nth_back(self: &mut Self, n: usize) -> Option<<Self as >::Item>

Returns the nth element from the end of the iterator.

This is essentially the reversed version of [Iterator::nth()]. Although like most indexing operations, the count starts from zero, so nth_back(0) returns the first value from the end, nth_back(1) the second, and so on.

Note that all elements between the end and the returned element will be consumed, including the returned element. This also means that calling nth_back(0) multiple times on the same iterator will return different elements.

nth_back() will return None if n is greater than or equal to the length of the iterator.

Examples

Basic usage:

let a = [1, 2, 3];
assert_eq!(a.iter().nth_back(2), Some(&1));

Calling nth_back() multiple times doesn't rewind the iterator:

let a = [1, 2, 3];

let mut iter = a.iter();

assert_eq!(iter.nth_back(1), Some(&2));
assert_eq!(iter.nth_back(1), None);

Returning None if there are less than n + 1 elements:

let a = [1, 2, 3];
assert_eq!(a.iter().nth_back(10), None);

fn try_rfold<B, F, R>(self: &mut Self, init: B, f: F) -> R
where
    Self: Sized,
    F: FnMut(B, <Self as >::Item) -> R,
    R: Try<Output = B>

This is the reverse version of [Iterator::try_fold()]: it takes elements starting from the back of the iterator.

Examples

Basic usage:

let a = ["1", "2", "3"];
let sum = a.iter()
    .map(|&s| s.parse::<i32>())
    .try_rfold(0, |acc, x| x.and_then(|y| Ok(acc + y)));
assert_eq!(sum, Ok(6));

Short-circuiting:

let a = ["1", "rust", "3"];
let mut it = a.iter();
let sum = it
    .by_ref()
    .map(|&s| s.parse::<i32>())
    .try_rfold(0, |acc, x| x.and_then(|y| Ok(acc + y)));
assert!(sum.is_err());

// Because it short-circuited, the remaining elements are still
// available through the iterator.
assert_eq!(it.next_back(), Some(&"1"));

fn rfold<B, F>(self: Self, init: B, f: F) -> B
where
    Self: Sized,
    F: FnMut(B, <Self as >::Item) -> B

An iterator method that reduces the iterator's elements to a single, final value, starting from the back.

This is the reverse version of [Iterator::fold()]: it takes elements starting from the back of the iterator.

rfold() takes two arguments: an initial value, and a closure with two arguments: an 'accumulator', and an element. The closure returns the value that the accumulator should have for the next iteration.

The initial value is the value the accumulator will have on the first call.

After applying this closure to every element of the iterator, rfold() returns the accumulator.

This operation is sometimes called 'reduce' or 'inject'.

Folding is useful whenever you have a collection of something, and want to produce a single value from it.

Note: rfold() combines elements in a right-associative fashion. For associative operators like +, the order the elements are combined in is not important, but for non-associative operators like - the order will affect the final result. For a left-associative version of rfold(), see [Iterator::fold()].

Examples

Basic usage:

let a = [1, 2, 3];

// the sum of all of the elements of a
let sum = a.iter()
           .rfold(0, |acc, &x| acc + x);

assert_eq!(sum, 6);

This example demonstrates the right-associative nature of rfold(): it builds a string, starting with an initial value and continuing with each element from the back until the front:

let numbers = [1, 2, 3, 4, 5];

let zero = "0".to_string();

let result = numbers.iter().rfold(zero, |acc, &x| {
    format!("({x} + {acc})")
});

assert_eq!(result, "(1 + (2 + (3 + (4 + (5 + 0)))))");

fn rfind<P>(self: &mut Self, predicate: P) -> Option<<Self as >::Item>
where
    Self: Sized,
    P: FnMut(&<Self as >::Item) -> bool

Searches for an element of an iterator from the back that satisfies a predicate.

rfind() takes a closure that returns true or false. It applies this closure to each element of the iterator, starting at the end, and if any of them return true, then rfind() returns Some(element). If they all return false, it returns None.

rfind() is short-circuiting; in other words, it will stop processing as soon as the closure returns true.

Because rfind() takes a reference, and many iterators iterate over references, this leads to a possibly confusing situation where the argument is a double reference. You can see this effect in the examples below, with &&x.

Examples

Basic usage:

let a = [1, 2, 3];

assert_eq!(a.into_iter().rfind(|&x| x == 2), Some(2));
assert_eq!(a.into_iter().rfind(|&x| x == 5), None);

Iterating over references:

let a = [1, 2, 3];

// `iter()` yields references i.e. `&i32` and `rfind()` takes a
// reference to each element.
assert_eq!(a.iter().rfind(|&&x| x == 2), Some(&2));
assert_eq!(a.iter().rfind(|&&x| x == 5), None);

Stopping at the first true:

let a = [1, 2, 3];

let mut iter = a.iter();

assert_eq!(iter.rfind(|&&x| x == 2), Some(&2));

// we can still use `iter`, as there are more elements.
assert_eq!(iter.next_back(), Some(&1));